Scarecrow45 (Member) asked a question. 300 DPI or 600 DPI for line art in book? I'm going to publish a 24-page black and white illustrated with line art children's book. There will be no bleed and apparently the book size will be 8.5 by 11 in. Images will be PNG format. However, I have seen conflicting information about DPI.
Now, the resolution is expressed in dpi (or ppi), which is the acronym for dots (or pixels) per inch. So, if you see 72 dpi it means that the image will have 72 pixels per inch; if you see 300 dpi means 300 pixels per inch, and so on. The final size of your image depends on the resolution that you choose.The following example will print the first field (line 1) at 150 dpi and the second (line 2) at 300 dpi: ^XA ^MUd,150,300 ^FT200,100^A0I,50,50^FDline 1^FS ^MUd,300,300 ^FT200,150^A0I,50,50^FDline 2^FS ^PQ1 ^XZ. In case it is needed to print all the text field with a lower resolution, the code must be modified as the following:DPI and Megabytes how to calculate. The short answer is no. You can calculate the number of pixels by multiplying each linear dimension of the source in inches by the DPI figure and then multiplying both these numbers together. After you know the number of pixels, you can then multiply by either 3 for 24 bit color depth or 6 for 48 bit color depth. The 200 dpi image is much larger on the screen, about 3 times larger. It contains correspondingly greater detail. And our so-called 72 dpi monitors will certainly show all of that detail, because the screen simply presents every image pixel, one by one. We are obviously NOT limited to 72 dpi, and 72 dpi is not a valid concept. The 200 dpi image As the svg standard output is 96 dpi my ratio will be: 755.906 px / 96 dpi = 7.874 in. Now if I want export at 200 x 200 at 300 DPI, it calculates that my pixel will increase up to 2362 x 2362 px and if I divide this size for my ratio the result is: 2362 px / 7.874 in = 299.9746 dpi, not 300 dpi. Now I want rounded my sizes at 756 dpi and my IJXT.